C++: Regex pattern
Clash Royale CLAN TAG#URR8PPPC++: Regex pattern
I got a regex pattern: (~[A-Z]){10,30} (Thanks to KekuSemau). And I need to edit it, so it will skip 1 letter. So it will be like down below.
Input: CABBYCRDCEBFYGGHQIPJOK
Output: A B C D E F G H I J K
[A-Z]([A-Z])?
What's with the
~? Just replace .(.) with ` $1` (space+$1). See it here at regex101.– ClasG
15 hours ago
~
.(.)
2 Answers
2
Just match two letters each iteration but only capture the second part.
(?:~[A-Z](~[A-Z])){5,15}
live: https://regex101.com/r/pIAxH8/1
I cut the repetition count (the bit inside the {}'s) by half since the new regex is matching two at a time.
The ?: in (?:...) bit disables capturing of the group.
?:
(?:...)
In regex only, there is no way you can achieve this directly.
But you can do this in code:
Use following regex:
(.(?<pick>[A-Z]))+
and in code make a loop on "captures" of desired group, like in c#:
string value = "";
for (int i = 0; i < match.Groups["pick"].Captures.Count; i++)
{
value = match.Groups["pick"].Captures[0].Value;
}
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Perhaps for that input you could match the first character and capture the second character in a group and replace with a whitespace and the capturing group
[A-Z]([A-Z])?– The fourth bird
17 hours ago