Counting all the numbers from a text file with re?

Clash Royale CLAN TAG#URR8PPPCounting all the numbers from a text file with re?
I am with the basics of RE, I need open a file with a lot of lines, take only the numbers and shows the average. This is my poor try:
import re
try:
ufile = open(input('What file are you using? '))
except:
print('File don't founded.')
exit()
lnumbers =
for line in ufile:
numbers = re.findall('([0-9.]+) ', line)
if len(numbers) > 0:
lnumbers.append(numbers)
I don't know what to do next.
1 Answer
1
Assuming that a given number would never wrap around from one line to the next, then a slight modification of your code should work:
for line in ufile:
numbers = re.findall('[0-9]+(.[0-9]+)?', line)
for number in numbers:
lnumbers.append(numbers)
if len(lnumbers) > 0:
print sum(lnumbers) / len(lnumbers)
else:
print "no numbers were found"
'1.....2'
@G_M Fine. I fixed it.
– Tim Biegeleisen
3 mins ago
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'1.....2'is a number?– G_M
4 mins ago