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Barcode scanner app parses barcode string to URL

I'm trying to build an app for learning purposes. It's a simple QR code and Barcode scanner app with a two flows:

I have achieved goal number one with the if statement

public void handleResult(Result result) {
final String myResult = result.getText();
Log.d("QRCodeScanner", result.getText());
Log.d("QRCodeScanner", result.getBarcodeFormat().toString());

if(Patterns.WEB_URL.matcher(result.getText()).matches()) {
// Open URL
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(result.getText()));
startActivity(browserIntent);
}
}


My challenge is now with goal number to which I just can't get to compile. I was thinking using an else statement and parse Uri with something like google.com + the string. The expected result is that if the scanner returns and value which is not a URL pattern open the browser go to google and search with the return value.

I hope I make myself clear. Pretty much a newbie here - trying to learn terminology and way to communicate.

3 Answers
3

please try this

public void handleResult(Result result) {
final String myResult = result.getText();
Log.d("QRCodeScanner", result.getText());
Log.d("QRCodeScanner", result.getBarcodeFormat().toString());

if(Patterns.WEB_URL.matcher(result.getText()).matches()) {
// Open URL
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(result.getText()));
startActivity(browserIntent);
}
else
{
String scannedResult = result.getText().toString();
String url = "https://www.google.com/search?q="+scannedResult;
Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
startActivity(browserIntent);
}
}


Use this to meet your requirement.

String query=result.getText();
if(Patterns.WEB_URL.matcher(query).matches()) {
// Open URL
Intent browserIntent = new Intent(Intent.ACTION_VIEW,
Uri.parse(result.getText()));
startActivity(browserIntent);
}else{
//Open url with google query
String escapedQuery = URLEncoder.encode(query, "UTF-8");
Uri uri = Uri.parse("http://www.google.com/#q=" + escapedQuery);
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);
}


Just simply put this code in your else condition

else{
Intent intent = new Intent(Intent.ACTION_WEB_SEARCH);
intent.putExtra(SearchManager.QUERY, result.getText());
startActivity(intent);
}


Let me know if it works

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