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Sum Function with array argument

i'm starting studying javascript. I'm stuck with this exercise: Create a function that takes an array as argument and return the sum of all elements of the array.
I have written this code:

function sum(table) {
let x = table[0];
let y = [table.length - 1];
let totale = 0;
for (count = x; count <= y; count++) {
total += x;
x += 1;
};
return total;
};


console.log(sum[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]);

I don't know why the result is undefined instead of 55. Thanks for helping.

let y = [table.length - 1];

y

totale

total

0

table[0]

2 Answers
2

total

totale

sum([…])

y = table.length - 1

x = 0

total += table[count];

function sum(table) {
let x = 0;
let y = table.length - 1;
let total = 0;
for (count = x; count <= y; count++) {
total += table[count];
};
return total;
};


console.log(sum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]));

function sum(table) {
return table.reduce((p,c)=>p+c,0);
};


console.log(sum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]));

reduce

Here are couple of things.

You need to execute the sum function by calling like sum([array elements]) .Note the ( & ) braces
Secondly count <= y will give undefined as it will exceed the length of the array. The array index starts from 0;

sum([array elements])

(

)

count <= y

There is a typo here totale.

totale

You can avoid these set of lines

let x = table[0];
let y = [table.length - 1];


if you just initialize the loop conditional statement like this

for (let count = 0; count < table.length; count++)


function sum(table) {
let x = 0
for (let count = 0; count < table.length; count++) {
x += table[count];
};
return x;
};
console.log(sum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]));

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