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How to openRow (leftSwipe) dynamically in react native

I am using react-native-base to swipable list. As per the code below, Every row will have "md-remove-circle" icon and I want to open row (leftSwipe) by clicking on the "md-remove-circle" icon. It is possible to openRow dynamically by function call ?

<List
dataSource={this.ds.cloneWithRows(this.state.listViewData)}
renderRow={ (data, secId, rowId, rowMap) =>

<ListItem style={{borderBottomWidth: 1,marginLeft: 0, backgroundColor : data.rowBg}}>

<Left>
{
this.state.rmvCircle &&

<Icon onPress={()=>this.openCurrenRow()} style={{color:'red'}} name="md-remove-circle" />
}

<TouchableOpacity onPress={()=>this.redir(data)}>
<Text>
{data.text}
</Text>
</TouchableOpacity>
</Left>
</ListItem>}


renderRightHiddenRow={(data, secId, rowId, rowMap) =>
<Button
full
danger
onPress={_ => this.clearNotificationPrompt(secId, rowId, rowMap, data.logId,'single')}
style={{
flex: 1,
alignItems: "center",
justifyContent: "center"
}}
>
<Icon active name="trash" />
</Button>}
leftOpenValue={this.state.leftOpenValue}
rightOpenValue={this.state.rightOpenValue}
/>


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