pgsql query to return single row to find the total count of diff columns on the same date

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pgsql query to return single row to find the total count of diff columns on the same date



I have a table that contains discount codes coupon_code and its vendor name.
eg: coupon_code: abc vendor: newyork
coupon_code: def vendor: usa
Another table has order details which contains date,coupon_code,order_number
eg:



date: 2012-04-07 coupon_code:abc order_number:1
date: 2012-04-08 coupon_code:abc order_number:2
date: 2012-04-08 coupon_code:def order_number:3
date: 2012-04-09 coupon_code:abc order_number:4



How can i get the total number of codes used for each day?
expected result



eg: date newyork[abc] usa[def]
2012-04-07 1 0
2012-04-08 1 1
2012-04-09 1 0




1 Answer
1



Try this


Select date,
count(case when coupon_code = 'abc' then 1 else null end) as newyork,
count(case when coupon_code = 'def' then 1 else null end) as usa
From tbl
group by date






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