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Query firebase to return if value more then number

I want to get data from Firebase.

This is more or less my db structure:

"Reports" : {
"N06Jrz5hx6Q9bcVDBBUrF3GKSTp2" : 2,
"eLLfNlWLkTcImTRqrYnU0nWuu9P2" : 2
},
"Users":{
"N06Jrz5hx6Q9bcVDBBUrF3GKSTp2" : {
"completedWorks" : {
...
},
"reports" : {
"-LHs0yxUXn-TQC7z_MJM" : {
"category" : "Niewyraźne zdjęcie",
"creatorID" : "z8DxcXyehgMhRyMqmf6q8LpCYfs1",
"reportedID" : "N06Jrz5hx6Q9bcVDBBUrF3GKSTp2",
"resolved" : false,
"text" : "heh",
"workID" : "-LHs-aZJkAhEf1RHVasg"
},
"-LHs1hzlL4roUJfMlvyA" : {
"category" : "Zdjęcie nie przedstawia zadania",
"creatorID" : "z8DxcXyehgMhRyMqmf6q8LpCYfs1",
"reportedID" : "N06Jrz5hx6Q9bcVDBBUrF3GKSTp2",
"resolved" : false,
"text" : "",
"workID" : "-LHs-aZJkAhEf1RHVasg"
}
},
"userType" : "company",
"verified" : true
},
}


So as you can see the number of reports is listed in the Reports part. How can I make Firebase return only the ids of the users where the report number is over or equal 3?

Reports

Something like this (this will not work, but I hope kind of shows what I was thinking about):

firebase.database().ref('Reports').orderBy(whatHere?).moreThen(2).on('value', snap => {


Is this even doable like this? If yes how could I do it? I want to grab the IDs of the users where reports are >= 3

1 Answer
1

There are two options for doing that but not exactly the way you wants. You have to use javascript for further processing. One is to use limitToLast after using order by. which will give the last numbers from the result.

limitToLast

firebase.database().ref('Reports').orderBy(reportid).limitToLast(2).on('value', snap => {


Or use startAt and endAt to skip and fetch the result as offset which can provide the data between two reportId.

startAt

endAt

offset

firebase.database().ref('Reports').orderBy(reportid).
.startAt(reportIdStart)
.endAt(reportIdLast)
.limitToLast(15)


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