Regular expression to get internal links only

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Regular expression to get internal links only



I am trying to get internal links only with the following code.


$domain="http://www.nydailynews.com";
$data = file_get_contents($domain);
$content=preg_match( '(.*'.$domain.'.*)|(^/.*$)', $domain, $matches );



but getting this error


Warning: preg_match(): Unknown modifier '|' in C:xampphtdocscrawlcrawlindex.php on line 4



what should be the regular expression for that so I can get sub pages of a website?





You need to add delimiters around your regex like this: /(.*' . $domain . '.*)|(^/.*$)/. What do you mean with "sub-pages" of a website? The path? Take a look at parse_url() then.
– Heyne
1 hour ago




/(.*' . $domain . '.*)|(^/.*$)/


parse_url()





@Heyne added that, but now it says Warning: preg_match(): Unknown modifier '/'
– e2e
55 mins ago





This is because your $domain variable holds a string with the delimiter '/' so you need to escape it like this: $content=preg_match( '/(.*'.preg_quote($domain, '/').'.*)|(^/.*$)/', $domain, $matches );
– Karol Samborski
7 mins ago


$domain


$content=preg_match( '/(.*'.preg_quote($domain, '/').'.*)|(^/.*$)/', $domain, $matches );




1 Answer
1



Just try this, it works


<?PHP
// Original PHP code by Chirp Internet: www.chirp.com.au
// Please acknowledge use of this code by including this header.

$url = "http://www.nydailynews.com";
$input = file_get_contents($url) or die("Could not access file: $url");
$regexp = "<as[^>]*href=("??)([^" >]*?)\1[^>]*>(.*)</a>";
if(preg_match_all("/$regexp/siU", $input, $matches, PREG_SET_ORDER)) {
foreach($matches as $match) {

echo $match[2]."<br/>";

}
}
?>






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