Regex for finding between 1 and 3 character in a string
Clash Royale CLAN TAG#URR8PPPRegex for finding between 1 and 3 character in a string
I am trying to write a regex which should return true, if [A-Za-z] is occured between 1 and 3, but I am not able to do this
public static void main(String args) {
String regex = "(?:([A-Za-z]*){3}).*";
String regex1 = "(?=((([A-Za-z]){1}){1,3})).*";
Pattern pattern = Pattern.compile(regex);
System.out.println(pattern.matcher("AD1CDD").find());
}
Note: for consecutive 3 characters I am able to write it, but what I want to achieve is the occurrence should be between 1 and 3 only for the entire string. If there are 4 characters, it should return false. I have used look-ahead to achieve this
Try
^[^A-Za-z]*[A-Za-z](?!(?:[^A-Za-z]*[A-Za-z]){3}). See live demo here regex101.com/r/a0eZx2/1– revo
2 mins ago
^[^A-Za-z]*[A-Za-z](?!(?:[^A-Za-z]*[A-Za-z]){3})
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Could you add some inputs and outputs for better understanding.
– JavaFan
3 mins ago