Regex to match 2 digit but different numbers
Clash Royale CLAN TAG#URR8PPPRegex to match 2 digit but different numbers
I'm working regex in recent days and now need to make regex which is match with 2 digit but the digits should be different each other
For example followings will be matched:
56, 78, 20 ...
But followings should not be matched:
22, 33, 66 or 99
Already wasted few days for this solution. So any suggestion will be welcome.
1 Answer
1
Capture the first digit, then use negative lookahead with a backreference to that first digit to ensure it isn't repeated:
(d)(?!1)d
https://regex101.com/r/AxH6s8/1
If you need a named group instead:
(?<first>d)(?!k<first>)d
For a general solution of n digits in a row without any repeated digits, you can do something similar, except put d* inside the negative lookahead, before the backreference:
n
d*
^(?:(d)(?!d*g{-1}))+$
https://regex101.com/r/AxH6s8/2
Not sure what language you're using, but you can use
(?<first>d)(?!k<first>)d– CertainPerformance
8 hours ago
(?<first>d)(?!k<first>)d
I'm using php, and I can't share full regex here. How about to name the first digit as "FirstDigit" such as following
(?'FirstDigit'[0-9])(?!(FirstDigit))[0-9] Of course this isn't work so I need to fix that correctly– rener172846
8 hours ago
(?'FirstDigit'[0-9])(?!(FirstDigit))[0-9]
@rener172846 Another alternative is to use a relative backreference, e.g.
(d)(?!g{-1})d which can save naming things you don't otherwise need to.– Paul Crovella
8 hours ago
(d)(?!g{-1})d
@CertainPerformance if the length of digit isn't fixable, is that still possible with only regex? For example, the number can be any of 4 - 8 digit, and there shouldn't be any same value. so 1245, 24567, 46735 are all match, but 11456, 145467 or 356787 are not match.
– rener172846
1 hour ago
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good work. but would you make an example with named group? because my regex is so complex and I can't index them as "1" or "2" simply.
– rener172846
8 hours ago