Clash Royale CLAN TAG

Convert ISO date string to Timestamp

String startDate = "2018-07-29T09:50:49+05:30";


String TAG = "Extra";
final String TIMESTAMP_FORMATE = "yyyy-MM-dd'T'HH:mm:ss.SSSXXX";

DateFormat df = new SimpleDateFormat(TIMESTAMP_FORMATE);
try {
Date date = df.parse(startDate);
System.out.println(TAG + "Start: " + date.getTime());
System.out.println(TAG + "Start: " + date.getDate());
System.out.println(TAG + "Start: " + date.getHours() + ":" + date.getTime());
} catch (ParseException e) {
e.printStackTrace();
}


Its giving an error java.text.ParseException: Unparseable date: "2018-07-29T09:50:49+05:30"

java.text.ParseException: Unparseable date: "2018-07-29T09:50:49+05:30"

Any idea what I am missing here?

.SSS

java.util.time

3 Answers
3

.SSS is for milliseconds, you do not need it, try:

.SSS

final String TIMESTAMP_FORMATE = "yyyy-MM-dd'T'HH:mm:ssXXX";


You can try this

String time="2018-07-29T09:50:49+05:30";
int ind = time.lastIndexOf('+');
time = time.substring(0, ind);
time = time+"Z";
System.out.println(time);
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
try
{
Date date = dateFormat.parse(time.replaceAll("Z$", "+0000"));
System.out.println(date);
String TAG = "Extra";
System.out.println(TAG + "Start: " + date.getTime());
System.out.println(TAG + "Start: " + date.getDate());
System.out.println(TAG + "Start: " + date.getHours() + ":" + date.getTime()) ;
}


The new API turns out to be even easier in this case. Your pattern is the default format for java.time.ZonedDateTime:

java.time.ZonedDateTime

ZonedDateTime date = ZonedDateTime.parse("2018-07-29T09:50:49+05:30")


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