How is “infinity” of type Double in Java
Clash Royale CLAN TAG#URR8PPPHow is “infinity” of type Double in Java
This may be a very simple question but I am very confused here.
Double.MAX_VALUE gives 1.7976931348623157E308 which indeed is a floating point literal and hence double.
Double.MAX_VALUE
1.7976931348623157E308
double
However, Double.POSITIVE_INFINITY gives infinity. How is infinity of type Double? It doesn't look like a decimal number or even a number.
Double.POSITIVE_INFINITY
Double
Please explain.
When you say "gives", are you meaning the string representation? The way a double is converted to a string is described in detail in the Javadoc.
– Andy Turner
10 mins ago
Maybe you can find the desired answer here: JLS §4.2.3.
– L.Spillner
3 mins ago
2 Answers
2
At a binary level in IEEE 754 (which is not exactly the same as Java floating point), infinity is represented as:
Positive and negative infinity are represented thus:
sign = 0 for positive infinity, 1 for negative infinity.
biased exponent = all 1 bits.
fraction = all 0 bits.
POSITIVE_INFINITY (and its counterpart, NEGATIVE_INFINITY) are special constants that Java uses to notify you of overflow of certain operations where the result can no longer be represented as a Double (or Float) value, e.g.
POSITIVE_INFINITY
NEGATIVE_INFINITY
System.out.println( 1E300 * 1E20 ); // Infinity
System.out.println( –1E300 * 1E20 ); // -Infinity
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It's a special case
– Maurice Perry
11 mins ago