What value will return when I opearte transform?.invoke() if transform is null in Kotlin?
What value will return when I opearte transform?.invoke() if transform is null in Kotlin?
I was told that invoke()
can be operated safely.
invoke()
1: What value will return when I operate transform?.invoke()
in Code A?
I think the Code val str = transform?.invoke(element) ?: element.toString()
is equivalent to the following code, right?
transform?.invoke()
val str = transform?.invoke(element) ?: element.toString()
val temp= transform?.invoke(element)
val str=temp?: element.toString()
2: I don't know whether .let
is another choice in Code B, could you tell me?
.let
Code A
fun <T> Collection<T>.joinToString(
separator: String = ", ",
prefix: String = "",
postfix: String = "",
transform: ((T) -> String)? = null
): String {
val result = StringBuilder(prefix)
for ((index, element) in this.withIndex()) {
if (index > 0) result.append(separator)
val str = transform?.invoke(element) ?: element.toString()
result.append(str)
}
result.append(postfix)
return result.toString()
}
Code B
fun <T> Collection<T>.joinToString(
separator: String = ", ",
prefix: String = "",
postfix: String = "",
transform: ((T) -> String)? = null
): String {
val result = StringBuilder(prefix)
for ((index, element) in this.withIndex()) {
if (index > 0) result.append(separator)
var str =element.toString()
transform?.let{
str=transform(element)
}
result.append(str)
}
result.append(postfix)
return result.toString()
}
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