Remove duplicates in array with a condition Java

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Remove duplicates in array with a condition Java



I have a task, to remove duplicates in array, what by "remove" means to shift elements down by 1, and making the last element equal to 0,
so if I have int array = {1, 1, 2, 2, 3, 2}; output should be like:
1, 2, 3, 0, 0, 0
I tried this logic:


1


0


int array = {1, 1, 2, 2, 3, 2};


1, 2, 3, 0, 0, 0


public class ArrayDuplicates {
public static void main(String args) {
int array = {1, 1, 2, 2, 3, 2};
System.out.println(Arrays.toString(deleteArrayDuplicates(array)));
}

public static int deleteArrayDuplicates(int array) {
for (int i = 0; i < array.length; i++) {
for (int j = i + 1; j < array.length; j++) {
if (array[i] == array[j]) { //this is for comparing elements
for (; i > 0; i--) {
array[j + 1] = array[j]; //this is for shifting
}
array[array.length - 1] = 0; //making last element equal to "0"
}
}
}
return array;
}
}



But it doesn't work.. Is anyone familiar with a right solution?
I appreciate your assistance and attention very much.









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